Mathematics, 06.02.2022 01:00 anasc

I need help as soon as possible. Find the real or imaginary solutions of each equation by factoring. ( I need an explanation I don’t understand) 27x^3+1=0

And

X^3-27=0

I need help as soon as possible. Find the real or imaginary solutions of each equation by factoring

Answers: 2

Show answers

Answers

Answer from: yatish

Let's solve these questions :

27x^3+1=0

Taking 1 to the right side as 0 has no use in the equation,

$↪ 27{x}^{3} = - 1$

$↪ {x}^{3} = - \frac{1}{27}$

$↪x = \sqrt[3]{ - \frac{1}{27} }$

Now, as 27 is the cube of 3,

$↪x = - \frac{1}{3}$

So, $x = \frac{1}{3}$

Now Second question,

x^3-27=0

Taking the negative 27 to the right side, it becomes positive.

$↪ {x}^{3} = 27$

$↪x = \sqrt[3]{27}$

↪x = 3

So value of x is 3

~ Benjemin360

Answer from: Lalagrl

Step-by-step explanation:

These questions are both to practice factoring a "sum/difference of two cubes" Someone else back in the 1500's figured out how to factor this. We just have to follow the pattern. Memorize this pattern.

The sum or difference of two cubes factors into a binomial and a trinomial. For the binomial just peel off the exponent (the 3rd power) from both terms and thats the first factor. For the trinomial, change the power to a 2 for both terms, but put in between them another term that is the the two terms multiplied together.

Lets look at your #6)

27x^3 + 1

Rewrite 27 as 3^3 and 1 as 1^3.

(3x)^3 + 1^3

FIRST FACTOR:

Just rip off the exponents:

(3x + 1)

SECOND FACTOR:

(3x)^2 - 3x + 1^2

^^^see the first and last terms are the 3x and the 1 but now they have a exponent, power of 2.

In between the multiply the 3x and the 1 times together.

The binomial has the Same sign as your original question. The trinomial has signs Opposite, then the last sign is Alwayspositive. The acronym SOAP can help you remember. The + or - in the factors.

I wish this was just a factoring problem. But we have to solve too.

3x+1=0

3x = -1

x = -1/3

AND

(3x)^2 + 3x + 1 =0

9x^2 + 3x + 1 = 0

oh no, we can't factor this, we have to use Quadratic formula: a=9, b=3, c=1

x= (-3+-root(3^2-4*9*1))/2*9

x = (-3 +- root(-27))/18

x= (-3 +- 3iroot3)/18

x = (-1 +- i*root3)/6

This is two solutions. Bc of the +- in the final answer. Some texts/programs/teacher might require you to write an imaginary number in the form a+bi

So it would be:

-1/6 + (i*root3)/6 and

-1/6 - (i*root3)/6

And from above the third solution is -1/3

I need help as soon as possible. Find the real or imaginary solutions of each equation by factoring.

Answer from: Quest

answer: 2 and 1

step-by-step explanation: got this question

Answer from: Quest

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

Another question on Mathematics

Mathematics, 21.06.2019 16:00

Sorry guys but as you have a small brain

Answers: 1

Answer

Mathematics, 21.06.2019 16:30

Phyllis and chen are saving money to go to a football game. each friend starts with some money and saves a specific amount each week. phyllis made a graph to show the total she has saved at the end of each week. chen wrote an equation to show the total, y, he has saved at the end of each week, x. y = 15x + 15 compare the amount that each friend has when both friends start saving. select the correct answer from the drop-down menu to complete the statement. phyllis starts with $ and chen starts with $

Answers: 1

Answer

Mathematics, 21.06.2019 17:30

The manufacturer of a new product developed the following expression to predict the monthly profit, in thousands of dollars, from sales of the productwhen it is sold at a unit price of x dollars.-0.5x^2 + 22x - 224what is represented by the zero(s) of the expression? a.the profit when the unit price is equal to 0b.the unit price(s) when the profit is equal to 0c.the profit when the unit price is greatestd.the unit price(s) when profit is greatest

Answers: 3

Answer

Mathematics, 21.06.2019 18:30

If you have the following equation, 2/3x+5/6-x=2-3/4x what would you multiply each term by to get rid of all the fractions

Answers: 3

Answer

You know the right answer?

I need help as soon as possible. Find the real or imaginary solutions of each equation by factoring....

Questions