Graph the line that has a slope of 10 and includes the point (0, 0).

See attached graph

Step-by-step explanation:

The equation that has a slope of 10 and intersects (0,0) is:

y = 10x

The slope-intercept form of a straight line equation is y=mx+b, where m is the slope and b the y-intercept (the value of y when x = 0).  

In this case:

m = 10

b is 0 since the value of y when x = 0 is 0 (0,0).

See attached graph.

We are given the slope of the line and a point that it passes through, so we can use the Point-Slope formula:

Where

y1 is the y-coordinate of the point, m is the slope and x1 is the x-coordinate.

In this case:

y1=0

m=10

x1=0

Plug in the values:

Solve:

Now, how to graph the line?

Let's look at its equation.

First of all, it has a y-intercept of 0, which means the line touches the y-axis at (0,0)

Now, what about the slope? The slope is 10.

Thus

We move "up 10, over 1, up 10, over 1" and so on, until we have a line.

Then all we have to do is take a ruler and connect the points.

Hope it helps!

~Just a determined gal

#HaveAGreatDay

2500

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b