Proof: Let m any odd integer.
The definition of even integer gives,
m=2p
Here, p is also integer.
According to the question,
3m + 5=3(2p) + 5
=6p + 5
=2(3p) + 2(2) + 1
=2(3p + 4) + 1
Let, (3p + 4)=a
Here, a is integer.
The above relation implies that,
3m + 5=2a + 1
The above relation 3m + 5=2a + 1 implies the definition of odd integer.
Therefore, for all integers m, if m is even then 3m + 5 is odd.

answer: the common difference is -0.10

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

∠cbe and ∠deb are same-side interior angles.

i took the test

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.