Find the slope of the line that is parallel and perpendicular to the line through the pair of points (-2,-7) and (6,6) plss help pls

parallel slope = , perpendicular =

Step-by-step explanation:

to find slope, formula:

                                   :

                                   :

if parallel, same slope, so slope = 13/8

if perpendicular, slope = -1/n = -1/13/8 =  -8/13 is the perpendicular slope.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

do i do it on a graph?

step-by-step explanation: