Can you please solve

There orthocenter is on the triangle and coordinates are ( -3 , 2 )

Step-by-step explanation:

coordinates given : X(-3,2) , Y(5, 2) , Z( -3 , 6 )

XY, m = ( 2-2)/(5--3) = 0

equation = y - 2 = 0(x--3)

y = 2

YZ, m = (6-2)/(-3-5) = 4/-8 = -1/2

equation = y -6 = 2( x + 3)

                   y = 2x+12

Using simultaneous equation:

x = -3

So y = 2

Therefore coordinates: ( -3, 2 )

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.