One sample has ss=36 and a second sample has ss=24. A) if n= 5 for both samples, find each of the sample variances and compute the pooled variances. Because the samples are now the same size, you shoukd find that the pooled variances is exactly halfway between the two sample variances.
B) Now assume that n=5 for the first sample and n=13 for the first sample and n=13 for a second. Again, calculate, the two sample variances and the pooled variances. You should find that the pooled variance is closer to the variance for the larger sample

the answer is b i just did that

step-by-step explanation:

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

answer: the answer is b. i think hope i got it correct

step-by-step explanation: