Mathematics, 25.01.2022 02:10 jan1829
Selma walked from her home to her friend’s house.
The travel graph shows Selma’s journey to her friend’s house.
Selma spent 1 hour at her friend’s house.
She then walked home at a steady speed.
Selma took 45 minutes to walk home
What was the total distance that Selma walked?
Answers: 1
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In δabc, m∠acb = 90°, cd ⊥ ab and m∠acd = 45°. find: a find cd, if bc = 3 in
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Selma walked from her home to her friend’s house.
The travel graph shows Selma’s journey to her fr...
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