The area B(t) of the base of a pyramid is increasing at a rate of 4m²/s and the height h(t) of the pyramid is decreasing at a rate of 1m/s. At a certain instant t_0 the area of the base is 18m² and the height is 6m. what is the rate of change of the volume V(t) of the pyramid at that instant?

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

answer:

a=9

step-by-step explanation: lmk if you need a explanation