4) In the graph below, what is f(2)? 40
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Triangle jkl was dilated using the rule dm, 1/3 the image, triangle j’ k’ l’ is the result of the dilation. a.5 units b.7.5 units c.10 units d.12.5 units

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

What are the solutions of the system? solve by graphing. y = -x^2 -6x - 7 y = 2