Derivatives of cos2x+1 / sin2x ?

Since we know that,

cos2x= cos²x-sin²x=(cosx-sinx)(cosx+sinx)

And, sin2x=2sinx.cosx

Therefore,

1-sin2x= cos²x+sin²x-2sinx.cosx

1-sin2x= (cosx-sinx)²

Then let

y=cos2x/(1-sin2x)

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50