The conditional relative frequency table was generated using data that compares the number of voters in the last election and whether or not they worked on election day. Fifty people who voted and 85 people who did not vote were chosen at random and surveyed. A 4-column table with 3 rows. The first column has no label with entries did work, did not work, total. The second column is labeled did vote with entries 0. 64, 0. 36, 1. 0. The third column is labeled did not vote with entries 0. 4, 0. 6, 1. 0. The fourth column is labeled total with entries 0. 49, 0. 51, 1. 0. How many people in the survey worked on election day? 32 34 66 69.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

it is impossible.

the correct answer is 1.7