Swimming Pool On a certain hot summer's day, 691 people used the public swimming pool. The daily prices are $1.75 for children and $2.00 for adults. The receipts for admission totaled $1295.50.
How many children and how many adults swam at the public pool that day?

Number of children= 346

Number of adults= 345

Step-by-step explanation:

We can set up a system of equations to solve for the number of children and adults.

x= number of children

y= number of adults

We know that the total number of people at the swimming pool is 691, which is comprised of both children and adults. We can write this equation as...

x+y=691

We also know that children pay 1.75 dollars and adults pay 2 dollars, with a total of 1295.50 dollars.

1.75x+2y=1295.50

We can now solve the system with elimination by multiplying the first equation by negative 2.

x+y=691 -> -2x-2y= -1382

-2x-2y= -1382

1.75x+2y=1295.50

-0.25x=-86.5

x= 346

Now that we found the number of children, we can solve for the number of adults.

x+y=691

346+y=691

y= 345

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

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