If f(x)=12x-7 then,
f'(x)= ?

related to Derivatives of constant and linear functions. Would appreciate it if you could explain the answer as well thank you

Step-by-step explanation:

Let y=12x-7

Interchanging the role of x and y;

x=12y-7

x+7=12y

x+7/12=y

Therefore,f'(x)=x+7/12

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3