A bag contains 6 red, 5 blue, and 4 yellow marbles. Two marbles are drawn from the bag, but the first marble drawn is not replaced. What is the probability of selecting a red marble, and then a blue marble?

(p red) = 2/5

(p blue) = 5/14

Step-by-step explanation:

add to number of marbles to get how many are in the bag.

6 + 5 + 4 = 15

Find the probability of drawing a red marble.

(p red) = 6/15

reduce by 3

(p red) = 2/5

The marble isn't replaced, so now there are 14 marbles in the bag. Find the probability of drawing a blue marble.

(p blue) = 5/14

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

u

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*