Help please - corresponding parts of congruent triangles

79

Step-by-step explanation:

Solve for X first

(4x-10)=(2x+6)

4x−10−2x=6

2x−10=6

2x=6+10

2x=16

x= 16/2

x=8

Because x is 8, you can now solve 4x-10 and 2x+6.

4x-10

4(8)-10

32-10

22

2(8)+6

16+6

22

Both B and D are 22.

180-22

158

158/2

79

79+79+22=180

A, C, F, and E are all 79.

This means A=79

step-by-step explanation: noo

y > 1/3x

y < = -x + 4

hope this : )