It is given that 2x³-7x²+x+10 = (x - 1) Q(j) + R. Find the remainder R and polynomial Q(j).

Step-by-step explanation:

Divide the given by x - 1:

x - 1 | 2x³ - 7x² + x + 10 = 2x²- 5x - 4  rem 6

       | 2x³ - 2x²

               -5x² + x

              -5x² + 5x

                        - 4x + 10

                        - 4x + 4

                                  6

2x³-7x²+x+10 = (x - 1)(2x²- 5x - 4) + 6

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

whats the