Each interior angel of a regular polygon is 160°. How many sides does it have? Find the interior angel of a regular polygon with one-third number of sides as the first polygon. ⚠️Fake answer not allow. ✔️Best answer will be marked as brilliant.

EXPLANATION:

We know that

Each interior angle of a regular polygon of n sides is {(n-2)/n}×180°

Given,

Each interior angle of the regular polygon = 160°

⇛{(n-2)/n}×180° = 160°

⇛(n-2)/n = 160°/180°

⇛(n-2)/n = 8/9

Now, applying cross multiplication then, we get

⇛9(n-2) = 8n

⇛9n-18 = 8n

⇛9n -8n = 12

⇛n=12

The number of sides in the given regular polygon = 12

One third of 12 = 12/3 = 4

Now,

We have ,n = 4

Each interior angle of a regular polygon of n sides is {(n-2)/n}×180°

⇛{(4-2)/4}×180°

⇛(2/4)×180°

⇛180°/2

⇛90°

Each interior angle = 90°

Answer: •The number of sides in the given regular polygon =12 •The interior angle of one third of the number of sides of the first polygon is 90°.

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.