A Photograph enlarged to make a poster, the photograph is 10cm wide and 15cm high, The poster is 35cm wide, how high is the poster?

  52.5 cm

Step-by-step explanation:

Assuming the scale factor is the same in all directions, for poster height h, we have ...

  height/width = h/(35 cm) = (15 cm)/(10 cm)

  h = (35 cm)(15/10) = 52.5 cm . . . . . multiply by 35 cm

The poster is 52.5 cm high.

the input value is the number of times you fold it. the input value is also known as the x-value. 

the output value is its thickness. the output value is the y-value.

when you don't fold it all, the thickness will remain the same, which is 1. the ordered pair would be (0,1).

when you fold it once, the thickness will double from 1 to  2. the ordered pair would be (1,2).

when you fold it a second time, the thickness will double from 2 to  4. the ordered pair would be (2,4).

fold it one more time, and the thickness will be 8. the ordered pair is (3,8)

fold it the fourth time, and the thickness doubles. 8 x 2 = 16. the ordered pair is (4,16)

fold it the fifth time, and the thickness goes from 16 to 32. the ordered pair is (5,32)

the ordered pairs would be:

(0,1)

(1,2)

(2,4)

(3,8)

(4,16)

(5,32)

(6,64)

(7,128)

and so on : p

the question asks for 6 ordered pairs, so i bolded the first six.

now, the equation for this would be 

if we graph that, and we do the vertical line test, then we know this is a function.

it is a function because each x-value has a different y-value. there are no y-values that have the same x-values.

i have attached the graph of that line.

read more on -

step-by-step explanation:

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent