Normal systolic blood pressure is a function of age. For a woman, the normal systolic pressure, P, in millimeters of mercury (mm Hg) is modeled by P = 0.01 A2 + 0.05 A + 107

where A is age in years.

What is the approximate age of a woman whose normal systolic pressure measures 125 mm Hg?

  40

Step-by-step explanation:

You want to find A for P=125. Putting the known values into the equation, we can solve for A.

  125 = 0.01A² +0.05A +107

  A² +5A -1800 = 0 . . . . . . . . . subtract 125; multiply by 100

  (A +45)(A -40) = 0 . . . . . . factor

The positive value of A that makes a factor zero is A=40.

The approximate age of the woman is 40.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116