If two bodies of masses 2000 kg and 4000 kg are separated by a distance of 10m the gravitational force attraction between them is a)6.67×10‐¹¹N b)48.85×10^7N
c)53.36N
d)53.36×10^‐7N

d)53.36×10⁻⁷N

Step-by-step explanation:

The formula for gravitational force between two bodies is given by

F = G (Mm/r²)

Where,

F = gravitational force ( we are asked to find this)

G = gravitational constant = 6.674 x 10⁻¹¹

M = mass of one of the bodies = 4000 kg

m = mass of the the other body = 2000 kg

r = distance between the two bodies = 10m

substituting the above values into the equation:

F = G (Mm/r²)

= (6.674 x 10⁻¹¹) (4000)(2000) / (10²)

= 5.339 x 10⁻⁶

= 53.39 x 10⁻⁷  Newtons

The closest answer to this is d

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.