Omg need help asap, the ones who helped me thank u so much

angle 1 = 20; angle 2 = 160

Step-by-step explanation:

(x-12) + 5x = 180

6x-12 = 180 (add 12 to each side)

6x = 192 (divide each side by 6 to get x by itself)

x = 32

plug x into each equation

angle 1: 32-12=20; 20

angle 2: 32x5= 160; 160

Angle 1: 20

Angle 2: 160

Step-by-step explanation:

Angles 1 and 2 both add up to 180 degrees assuming that line is a straight line. Since we are given a system of equations for both angles, we can add them together, let them equal 180, and use the answder to plug them into respective equations to find the angle amount.

(x-12)+5x=180   (adding both of the angles together)

6x-12=180         (combine x)

6x=192

x=32                  (isolate x)

Since we now know what x stands for, we can plug this number in to angle 1's equation (x-12) to find that angle.

32-12=20         (m<1's angles)

We can do this for angle 2 as well.

5(32)=160         (m<2's angle)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

the answer is

d.

5.3066 m2

step-by-step explanation: