Answers: 2
, 
if and only if 
.
.
.
.
.
.![[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]](/tpl/images/2610/4520/b92f8.png)
for any element 
and 
. 
or 
(or both.)
.Similarly, if 
.![[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]](/tpl/images/2610/4520/ae7e0.png)
:
since the contrapositive of that statement, 
, is true. Therefore, 
.Otherwise, if 
, then 
implies 
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