How to factorise:

1) 9t²w - 3.

2) 4(x - 5)² + 3 (x - 5)

1.  

2.  

Step-by-step explanation:

For the first question, you simply get the common factor out of both values and in this case it is 3. So if you take 3 out of it is basically like dividing.

*You can't divide the alphabetic variables though* So it would be 3t^2w

Then, with -3 you again divide it by 3 so it would be -1.

Put them together and you get

3(3t^2w-1)

For the second question it has some more steps than the first one.

You first expand both of them:

4(x-5)(x-5) + 3x - 15

Then you should expand the double brackets using the foil method ( search it up if confused):

Then you simply the brackets where -5x and -5x makes -10x. Now take the whole bracket and times it by 4 :

Now you simplify again:

You then factorise this equation right here into a double bracket:

As you could see (x-5) is the same so it works!

then you factorise it to:

I hope it is right and if you see any mistakes pls feel free to ask :)

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2