The foci for the hyperbola (x-2)^2/36-(y+1)^2/64=1 are (2,-1+4sqrt7) and (2,-1-4sqrt7 true or false?

Enter a problem...

Precalculus Examples

Popular Problems Precalculus Graph ((x-2)^2)/36-((y+1)^2)/64=1

(

x

−

2

)

2

36

−

(

y

+

1

)

2

64

=

1

Simplify each term in the equation in order to set the right side equal to

1

. The standard form of an ellipse or hyperbola requires the right side of the equation be

1

.

(

x

−

2

)

2

36

−

(

y

+

1

)

2

64

=

1

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

(

x

−

h

)

2

a

2

−

(

y

−

k

)

2

b

2

=

1

Match the values in this hyperbola to those of the standard form. The variable

h

represents the x-offset from the origin,

k

represents the y-offset from origin,

a

.

a

=

6

b

=

8

k

=

−

1

h

=

2

The center of a hyperbola follows the form of

(

h

,

k

)

. Substitute in the values of

h

and

k

.

(

2

,

−

1

)

Find

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%