The sum of two numbers is 40. The larger number is 8 more than the smaller number. What are the numbers?

Hey There !

Let's solve....

Let the larger number be x

Let the smaller number be y

So

Now x+y=40

So just add 40+8=48

We know that

So larger number is 24

To find the smaller number.... Just subtract The total number by larger number that is

So 16 is the smaller number...

Larger number is 24 and smaller is 16

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