if the length of a rectangle is 4 more than the width and if the perimeter 0of rectangle is 52, what is the width of the rectangle

160

step-by-step explanation:

idk

i hope i

using pemdas, (order of operations) you'll see the answer is 24.

3+3+3+2*2*2+29*12 = 365

step-by-step explanation:

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.