A 1000 foot spool of bare 12-gauge copper wire weighs 19. 8 pounds. How much will 18 inches of the wire weigh, in ounces.

0.4752 ounces

Step-by-step explanation:

first, we can convert inches to feet to make the conversion easier as everything will be in one unit

12 inches = 1 foot

divide both sides by 12 inches to put the inches on the bottom so that when we multiply by 18 inches, the inches unit is crossed out

1 foot/ 12 inches = 1

18 inches * 1 foot / 12 inches = 18 inches * 1 = 18 feet/12 = 1.5 feet

1000 feet = 19.8 pounds

1.5 feet = ? ounces

we can find that 1000 * (1.5/1000) = 1.5 as the 1000s are crossed out and 1.5 remains. By multiplying both sides of the equation by (1.5/1000), we can find what the ? means as we can set the two equations equal to each other, like so:

1000 feet * (1.5/1000) = 19.8 * (1.5/1000)

1.5 feet = 0.0297 pounds

1.5 feet = ? ounces

0.0297 pounds = ? ounces

1 pound = 16 ounces

make sure pounds are at the bottom so we can cross them out

16 ounces / 1 pound = 1

0.0297 pounds * 16 ounces / 1 pound = 0.4752 ounces

b

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180