John is baking rectangular cakes. The first cake he baked was 3 inches wide and 5 inches long. The second cake he baked was 6 inches wide and 10 inches long. The third cake he baked was 12 inches wide and 20 inches long. If John continued this pattern, what would the dimensions of his fourth cake be?

24x40

Everytime the dimensions double, so the forth time the dimensions would be:

24 wide, 40 long.

24 in wide and 40 in  long.

Step-by-step explanation:

Each dimension is doubled:

width 3 goes to 6, and 6 goes to 12.

length 5 goes to 10, and 10 goes to 20.

So 4th cake will have dimension 2*12 and 2*20 in.

answer: t=3

step-by-step explanation:

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice