6. Two cars A and B 250 km apart are traveling towards each other on the same road. Car A travels at 55 km/h
while car B travels at 70 km/h.
(a) When will they meet on the road?
(b) Find the distance each car travels before they meet.

So car A travels Distance = 60 km/hr*(1+x)

Car B travels Distance = 75 km/hr(x)

Where x is the time in hours.

Those two equations are equal when on overtakes the other

so:

60 +60x = 75x

60=15x

x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.

At 2 hours they will meet on the road

Car A:  110 km;  Car B:  140 km

Step-by-step explanation:

Since the total distance is 250 km, we know that when the sum of the miles driven by each car adds to 250, they will meet.

Let x be the time, in hours.

              Miles Travelled

Car A             (55km/h)x

Car B             (70 km/h)x

(55km/h)x +  (70 km/h)x = 250

55x + 70x = 250

125x = 250

x = 2 hours  At 2 hours they will meet on the road

              Distance Travelled

Car A             (55km/h)2 =  110 km

Car B             (70 km/h)2 = 140 km

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.