Find three consecutive even integers such that the
sum of the smallest and the largest is 36.

n= smallest integer

n+2= middle integer

n+4= largest integer

n + n + 4 = 36

2n+ 4 = 36

2n=32

n= 16 which means that the smallest integer is 16

then you substitute it into the equation for the largest integer

n+4=20

16, 18, 20 is the answer

step-by-step explanation:

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%