The 3rd term and 6th term of ageometric progression are 108 and -32 respectively
find the sum of the first seven term?

Step-by-step explanation:

a + a r + a r^2 + a r^3 + a r^4 + a r^5 + ar^6

a r^2 = 108

a r^5 =-32

r^5/r^2 = - 32/108 = -8/27

r^3 = -2^3/3^3 =

r = - 2/3

if im undersanding the question correctly, its organized from 10

step-by-step explanation:

true? is that what you're asking or do you mean something else?