The diagonal of a side of rhombus are of equal length. Find the measures of angles of the rhombus.

Explanation:

Consider ABCD is a rhombus

We know that

All sides are equal in rhombus i.e,

⇛AB=BC=CD=DA

and AC and BD are digonals

Given that

Diagonal and the side of the rhombus are equal.

⇛AB = BC = CD = DA = AC

Diagonal AC divides the rhombus into two triangles .

They are ∆ BAC and ∆ DAC

In triangle BAC

BA=BC=AC,(Given)

⇛∠ BAC=∠ABC= ∠ACB =60°→→→Eqn(i)

Similarly in ∆DAC ,

DA=DC=AC

⇛∠DAC=∠ACD=∠ADC=60°→→→Eqn(ii)

From eqn(i) and eqn(ii)

∠A=∠BAC+∠DAC=60°+60°=120°

and

∠B= ∠ABC = 60°.

and

∠C=∠ACB+∠ACD=60°+60°=120°

and

∠D =∠ADC=60°

∴ ∠A = 120° , ∠B = 60° ,∠C = 120° & ∠D = 60°

-The measures of the all angles in the rhombus are 120° , 60° ,120° and 60°.

Note: [Figure refers in the attached file.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

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