Can someone teach me how to do this?

the formula is a_{1}+(n-1) d

so a_{1} would be the first number in the sequence, which would be 13 in problem 9.

13+(n-1)d

then you put in n, which is 10 (it represents which number in the sequence you're looking for, for example 16 is the second number in the sequence)

13+(10-1)d

then you find the difference between each number, represented by d which in this case is 3

13+(10-1)3

13+(9)3

13+27=

40

32

step-by-step explanation:

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all