Mathematics, 19.12.2021 14:00 ayoismeisalex

5) So far you have a MP3 Player with 0.5 GB of music already stored on the MP3 player and know that each song is about 0.002 GB of memory. What are the possible numbers of additional songs that you can put on the MP3 player if it holds at most 2 GB?

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Answer from: ronnie7898

Any whole number between 0 and 750, including both endpoints.

One example could be 700 additional songs.

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Explanation:

x = number of additional songs, some nonnegative whole number

1 song takes up 0.002 GB, so x of them take up 0.002x GB of memory.

Add on the 0.5 GB already used to get the expression 0.002x+0.5 to represent the total amount of storage taken up. We want this expression to be 2 or smaller.

$0.002x + 0.5 \le 2\\\\0.002x \le 2-0.5\\\\0.002x \le 1.5\\\\x \le 1.5/0.002\\\\x \le 750\\\\$

This says the most songs we can add are 750.

Because x is the number of songs, it doesn't make sense to have x be negative. This means $x \ge 0$ or $0 \le x$ is the case as well.

Combining $0 \le x$ and $x \le 750$ produces the compound inequality $0 \le x \le 750$

The number of additional songs is any whole number between 0 and 750, including both endpoints.

The roster notation of this set could look like this: {0, 1, 2, ..., 748,749,750}

The triple dots indicate "keep this pattern going". That way we don't have to fill in all 751 values which would be a tedious process.

So you can add on something like 700 songs because it's between those endpoints mentioned, but cannot add something like 800 songs.

Answer from: Quest

i cant answer this, theres no table. sorry man

step-by-step explanation:

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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5) So far you have a MP3 Player with 0.5 GB of music already stored on the MP3 player and know that...