Is it appropriate to use the geometric distribution to calculate probabilities in this situation? Yes, the geometric distribution is appropriate.
No, since each trial is not independent of the other trials.
No, because it is not looking for the first occurrence of success.
No, since the probability of success is not the same for each of the trials.

coins of silver or gold

step-by-step explanation:

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2