Mathematics, 16.12.2021 21:00 Alexishp33
Consider a binomial distribution with n = 10 trials and the probability of success on a single trial p = 0.85.
(a) Is the distribution skewed left, skewed right, or symmetric?
(b) Compute the expected number of successes in 10 trials.
(c) Given the high probability of success p on a single trial, would you expect P(r ≤ 3) to be very high or very low? Explain.
1) Very low. The expected number of successes in 10 trials is more than 3, and p is so high that it would be common to have so few successes in 10 trials.
2) Very high. The expected number of successes in 10 trials is more than 3, and p is so high that it would be unusual to have so few successes in 10 trials.
3) Very low. The expected number of successes in 10 trials is more than 3, and p is so high that it would be unusual to have so few successes in 10 trials.
4) Very high. The expected number of successes in 10 trials is more than 3, and p is so high that it would be common to have so few successes in 10 trials.
(d) Given the high probability of success p on a single trial, would you expect
P(r ≥ 8) to be very high or very low? Explain.
1) Very low. The expected number of successes in 10 trials is more than 8, and p is so high that it would be unusual to have 8 or more successes in 10 trials.
2) Very low. The expected number of successes in 10 trials is more than 8, and p is so high that it would be common to have 8 or more successes in 10 trials.
3) Very high. The expected number of successes in 10 trials is more than 8, and p is so high that it would be common to have 8 or more successes in 10 trials.
4) Very high. The expected number of successes in 10 trials is more than 8, and p is so high that it would be unusual to have 8 or more successes in 10 trials.
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Consider a binomial distribution with n = 10 trials and the probability of success on a single trial...
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