What is the solution to the following system of equations? −x−2y−4z=−6
x−5y−2z=−2
2x−3y+2z=2

y=-3

Step-by-step explanation:

[1]    x = 2y + 4z + 26

// Plug this in for variable  x  in equation [2]

  [2]    4•(2y+4z+26) - 2y + 4z = 6

  [2]    6y + 20z = -98

// Plug this in for variable  x  in equation [3]

  [3]    2•(2y+4z+26) + 2y - z = 6

  [3]    6y + 7z = -46

// Solve equation [3] for the variable  z

 [3]    7z = -6y - 46

 [3]    z = -6y/7 - 46/7

// Plug this in for variable  z  in equation [2]

  [2]    6y + 20•(-6y/7-46/7) = -98

  [2]     - 78y/7 = 234/7

  [2]     - 78y = 234

// Solve equation [2] for the variable  y

[2]    78y = - 234

  [2]    y = - 3

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.