AC =

a) 9

b) 4.5

c) 5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

for future students the answer is b

hope i

-lavira: )

true. i hope this ! go answer some of my newest

your answer is option c.