What is the domain of the function shown in the mapping? {x | x = –5, –3, 1, 2, 6}
{y | y = –9, –6, 0, 2, 4}
{x | x = –9, –6, –5, –3, 0, 1, 2, 4, 6}
{y | y = –9, –6, –5, –3, 0, 1, 2, 4, 6}

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

7

step-by-step explanation:

the answer would be 7

is this part of a question or something

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204