Question 16 (1 point) The students in a Statistics class at a local high school were surveyed. Two of the variables recorded for the 80 students were commuting
status and grade level. Commuting status was recorded as driving alone, carpooling, or being dropped off. Grade level was classified as
either junior or senior. The following table summarizes the responses. Based on the responses, what is the probability that a randomly
selected Statistics student from this school is a senior or gets dropped off?
Drives alone
Commuting Status Carpooling
Dropped off
Total
Grade level
Junior Senior Total
15 30 35
13 17 30
17 8 15
25 55 80
70/80
Ob
8/15
O
62/80
Od
8/55
Time left for this

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4