Add: (3x^3-3x^2+9) and (-7+5x^2+7x^3)

Given expressions are 3x³-3x²+9 and -7+5x²+7x³

On adding them

⇛ (3x³-3x²+9 ) + (-7+5x²+7x³)

⇛ 3x³-3x²+9 -7+5x²+7x³

⇛ (3x³+7x³)+(5x²-3x²)+(9-7)

⇛(3+7)x³+(5-3)x²+(2)

⇛ 10x³+2x²+2

Ans: (3x³-3x²+9 ) + (-7+5x²+7x³) = 10x³+2x²+2

also read similar questions: Add: a² + b² + c² – 3abc and a² – b² + c² + abc 2. Add: xy² + 4x²y – 7x²y - 3xy + 3 and x²y + xy² 3. Add: 5x² + 7y - 6z² ; 4y + 3x² ; 9x² + 2z² - 9y and 2y - 2...

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

step-by-step explanation:

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