Leslie ran 3 mile race. The second mile took her 10 percent longer than the first one and the third mile took her 24 seconds longer than the second mile. If Leslie’s total time for the race was 26 minutes how long did the second mile take her?

8.8 Minutes or 528 Second.

Step-by-step explanation:

↓[ Read Below ]↓

Important Info:

Leslie Ran 3 Mile Race.

2nd Mile = 10% longer than 1st and 3rd Miles took her 24s longer than 2nd Mile

Question to

Leslie’s total time for the race was 26 minutes how long did the second mile take her?

Explanation/Solution:

Let for first mile, she took x minutes . And second mile took her 10 percent longer, so second mile took

x+ 10/100x = 110/100x=1.1x

And the third mile took 24 seconds longer as compared to second mile .

So third mile took

1.1x+24/60 = (1.1x+0.4) Minutes

And the total time for the race was 26 minutes, that is

x+1.1x+1.1x+0.4=26

3.2x=26-0.4

3.2x=25.6

x= 25.6/3.2 = 8 Minutes

So the first mile took 8 minutes. And therefore second mile took

= 1.1 (8) = 8.8 Minutes

Also Equal to 528 Second.

[RevyBreeze]

answer: are you

step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1