Mathematics, 14.12.2021 18:20 hunter3978

Cho chuỗi số ∑n=1+∞1(8n−5)(8n+3) có tổng riêng Sn=13.11+111.19+119.27+...+1(8n−5)( 8n+3). Tổng của chuỗi số đã cho là:

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Cho chuỗi số ∑n=1+∞1(8n−5)(8n+3) có tổng riêng Sn=13.11+111.19+119.27+...+1(8n−5)( 8n+3). Tổng của c...

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