Mathematics, 12.12.2021 21:30 duracohack
The sum of four consecutive odd integers is โ72. Write an equation to model this situation, and find the values of the four integers.
A.
n + n + 2 + n + 4 + n + 6 = โ72; n = โ21; n + 2 = โ23; n + 4 = โ25; n + 6 = โ27
B.
n + (n โ 2) + (n โ 4) + (n โ 6) = โ72; n = โ 21; n โ 2 = โ23; n โ 4 = โ25; n โ 6 = โ 27
C.
n โ (n + 2) โ (n + 4) โ (n + 6) = โ72; n = โ20; n + 2 = โ18; n + 4 = โ16; n + 6 = โ14
D.
n + n + 2 + n + 4 + n + 6 = โ72; n = โ21; n + 2 = โ19; n + 4 = โ17; n + 6 = โ15
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