1) 4. Recall that the cost per number of wristbands is: f(x) =
2x + 20, 0 < x < 50
x + 10, 50 < x < 100
0.5x,
X > 100
O to 50 wristbands
51 to 100 wristbands
over 100 wristbands
What is the difference in cost between one order of 200 wristbands, two
orders of 100 wristbands each, and four orders of 50 wristbands each?
I

answer:     true

step-by-step explanation:

what i would say the best answer is a. 40.5

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)