The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel: (image)

Which statement best describes a flaw in the student's proof?

Angle DBC and angle BDA form a pair of vertical angles, not a pair of alternate interior angles, which are congruent.

Triangles ABD and CDB are congruent by the SAS postulate instead of the SSS postulate.

Triangles ABD and BCD are congruent by the AAS postulate instead of the SSS postulate.

Angle DBC and angle BDA form a pair of corresponding angles, not a pair of alternate interior angles, which are congruent.

29 is the correct answer

step-by-step explanation:

i think it is 70

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)