Find three consecutive integers such that three times the first increased by the third is equal to 42

equal to

step-by-step explanation:

step-by-step explanation:

there's the chart

4|x| - 1 < -4

we are given with absolute value inequality

lets make the absolute value alone

4|x| - 1 < -4

add 1 on both sides

4|x| - 1 +1 < -4 +1

4|x|   < -3

now divide by 4 on both sides

any absolute value cannot be negative.

absolute value function gives only the positive value.

so there is no solution for this problem.

there is no solution for this so its not possible to graph this inequality.