d is a point on the side bc of abc such that ad bisects the angle a. dx and dy are the perpendiculars from d to ab and ac, respectively. prove db/dc=ba/ac

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

jbankston is right, use thhe link and you should find the answer.

the answer, i believe is y-8=1(x+4)