A worm wriggled forward 4
5
of an inch in 3 minutes. At that rate, how far would the worm go in 1 minute?

4/15 of an inch

Step-by-step explanation:

=> At that rate, the distance the worm would go in 1 minute is:

D = (4/5)/3 = 4/(5x3) = 4/15 of an inch

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~Zero

4/15 of an inch

Step-by-step explanation:

A worm wriggled forward 4/5 of an inch in 3 minutes.

=> At that rate, the distance the worm would go in 1 minute is:

D = (4/5)/3 = 4/(5x3) = 4/15 of an inch

45 minutes

step-by-step explanation:

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: