A parallelogram with a diagonal drawn through it is shown below. Arlen is trying to prove that RS ≅ TU, but is unable to come up with one of the lines of the proof.

STATEMENTS REASONS
RSUT is a parallelogram Given
∠RST ≅ ∠UTS and ∠RTS ≅ ∠UST If parallel lines are cut by a transversal, alternate interior angles are congruent.
ST ≅ ST Reflexive Property
ΔRST ≅ΔUTS ???
RS ≅ TU Corresponding parts of a congruent triangle are congruent.

What is the missing reason in the proof?

step-by-step explanation:

my butt

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

$15 each

step-by-step explanation:

$45/3 children= $15 each

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm